若3x²-kx+4被3x-1除后余3,则k=_
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若3x²-kx+4被3x-1除后余3,则k=_若3x²-kx+4被3x-1除后余3,则k=_若3x²-kx+4被3x-1除后余3,则k=_因二次项系数为3,则设商为X+A
若3x²-kx+4被3x-1除后余3,则k=_
若3x²-kx+4被3x-1除后余3,则k=_
若3x²-kx+4被3x-1除后余3,则k=_
因二次项系数为3,则设商为X+A
(3X-1)×(X+A)+3
=3X²-X+3AX-A+3
=3X²-(1-3A)X+(3-A)
3-A=4
则A=-1
把A=-1代入1-3A中,得
1-3A=1+3=4
则K=4
k=4
3x²-kx+4被3x-1除后余3
3x²-kx+4-3被3x-1可整除
3x-1=0,x=1/3代入3x²-kx+1结果等于0
1/3-k/3+1=0
k=4
3x²-kx+4被3x-1除后余3,则k=4
k=4
由题意可得3x²-kx+1能被3x-1整除
3x²-kx+1=3x²-x+(1-k)x+1=x(3x-1)+[(1-k)x+1]
因为1=-1*(-1),所以+(1-k)x+1=-1*(3x-1),因此1-k=-3,k=4
3x^2 -kx +1 能被 3x -1 整除
设3x^2 -kx +1 =(3x-1)(x+a) = 3x^2 +(3a-1)x - a
a =-1 所以 k =1 -3a =4