已知x(x+y)-2y(x+y)=0求xy分之x2+y2的值

来源:学生作业帮助网 编辑:六六作业网 时间:2024/08/11 16:52:37
已知x(x+y)-2y(x+y)=0求xy分之x2+y2的值已知x(x+y)-2y(x+y)=0求xy分之x2+y2的值已知x(x+y)-2y(x+y)=0求xy分之x2+y2的值x(x+y)-2y(

已知x(x+y)-2y(x+y)=0求xy分之x2+y2的值
已知x(x+y)-2y(x+y)=0求xy分之x2+y2的值

已知x(x+y)-2y(x+y)=0求xy分之x2+y2的值
x(x+y)-2y(x+y)
= (x+y)(x-2y)
= 0
所以 x+y =0 或者 x -2y =0
如果 x+y =0,则
(x²+y²) /xy
= ((x+y)² -2xy) /xy
= (x+y)² /xy -2
= 0-2
= -2
如果 x-2y =0,则 x =2y
(x²+y²) /xy
= (4y²+y²) / (2y²)
= 5/2