若x2-2x+10+y2+6y=0,求(2x+y)2
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若x2-2x+10+y2+6y=0,求(2x+y)2若x2-2x+10+y2+6y=0,求(2x+y)2若x2-2x+10+y2+6y=0,求(2x+y)2x2-2x+10+y2+6y=0x²
若x2-2x+10+y2+6y=0,求(2x+y)2
若x2-2x+10+y2+6y=0,求(2x+y)2
若x2-2x+10+y2+6y=0,求(2x+y)2
x2-2x+10+y2+6y=0
x²-2x+1+y²+6y+9=0
(x-1)²+(y+3)²=0
x-1=0
y+3=0
∴x=1
y=-3
(2x+y)²=(2-3)²=1