化简[a-1+2/(a+1)]×1/a²+1
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化简[a-1+2/(a+1)]×1/a²+1化简[a-1+2/(a+1)]×1/a²+1化简[a-1+2/(a+1)]×1/a²+1a-1+2/(a+1)=(a^2-1+
化简[a-1+2/(a+1)]×1/a²+1
化简[a-1+2/(a+1)]×1/a²+1
化简[a-1+2/(a+1)]×1/a²+1
a-1+2/(a+1)=(a^2-1+2)/(a+1)=a^2+1/a+1
再乘以1/a^2+1等于1/(a+1)
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