设z=|1-2✔2i|-(2+3i),则|z|?

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设z=|1-2✔2i|-(2+3i),则|z|?设z=|1-2✔2i|-(2+3i),则|z|?设z=|1-2✔2i|-(2+3i),则|z|?|1-2√2i

设z=|1-2✔2i|-(2+3i),则|z|?
设z=|1-2✔2i|-(2+3i),则|z|?

设z=|1-2✔2i|-(2+3i),则|z|?
|1-2√2i| = √[1^2+(2√2)^2] = √(1+8) = √9 = 3
z = 3 - 2 -3i = 1 - 3i
|z| = √(1^2+3^2) = √10