(x1-x2)+(x2-x1)/(x1x2)分解因式我看不懂过程
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(x1-x2)+(x2-x1)/(x1x2)分解因式我看不懂过程(x1-x2)+(x2-x1)/(x1x2)分解因式我看不懂过程(x1-x2)+(x2-x1)/(x1x2)分解因式我看不懂过程原式=(
(x1-x2)+(x2-x1)/(x1x2)分解因式我看不懂过程
(x1-x2)+(x2-x1)/(x1x2)分解因式
我看不懂过程
(x1-x2)+(x2-x1)/(x1x2)分解因式我看不懂过程
原式=(x1-x2)(1-1/x1x2)
=(x1-x2)(x1x2-1)/x1x2
单调性证明里碰到的吧,一直要分解到这一步~~
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(x1-x2)+(x2-x1)/(x1x2)
=(x1-x2)(1-1/(x1x2) 提取公因式(x1-x2)
=(x1-x2)(x1x2-1)/x1x2 化简第二个括号的式子
(x1-x2)+(x2-x1)/(x1x2)=(x1-x2)[x1x2-1]/(x1x2)
(x1-x2)+(x2-x1)/(x1x2)=[(x1x2-1)(x1-x2)]/x1x2
先通分:(x1-x2) 乘以x1x2 / x1x2
(x1-x2)+(x2-x1)/(x1x2)
=(x1-x2)x1x2/x1x2+(x2-x1)/(x1x2)
={x1(x1x2-1)-x2(x1x2-1)}/x1x2
=[(x1x2-1)(x1-x2)]/x1x2
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