y=(2x^2-1)/(3x^2+2)值域
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y=(2x^2-1)/(3x^2+2)值域y=(2x^2-1)/(3x^2+2)值域y=(2x^2-1)/(3x^2+2)值域解y=(3x²+2)/(2x²-1)反解,可得:x
y=(2x^2-1)/(3x^2+2)值域
y=(2x^2-1)/(3x^2+2)值域
y=(2x^2-1)/(3x^2+2)值域
解
y=(3x²+2)/(2x²-1)
反解,可得:
x²=(2+y)/(2y-3).
易知,(2+y)/(2y-3)≥0 (∵x²≥0.)
∴(2y-3)(y+2)≥0
∴y≤-2或y>3/2
∴值域为:(-∝, -2]∪(3/2, +∞)
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