1/【2x+(1-x方/x)】=急a
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1/【2x+(1-x方/x)】=急a1/【2x+(1-x方/x)】=急a1/【2x+(1-x方/x)】=急a1/[2x+(1-x^2/x)]=1/[2x+(1-x)]=1/(2x+1-x)=1/(x+
1/【2x+(1-x方/x)】=急a
1/【2x+(1-x方/x)】=
急a
1/【2x+(1-x方/x)】=急a
1/[2x+(1-x^2/x)] = 1/[2x + (1 - x) ] = 1/ (2x + 1 - x) = 1/(x + 1)
不过我觉得这个题目是不是应该是
1/[2x + (1- x^2) / x] = 1/[(1+x^2)/x] = x/(1+x^2) = x + 1/x