m=a+[1/(a-2)],(a>2),n=(1/2)^(x*x-2),(x

已知a^3*a^m*a^2m+1=a^25,求m的值 a^m-1*a³-2a^m*a^4-3a²*a^m+2 2a^(2m+3)(-a)^2/(-a)^(m-1)=-2(a^3)^(m-1)/a m为多少 M=a+1/(a-2) (2 (-a)^2m+1÷a^m ..(1/a)^m=5 则a^-2m= a*a+4a+1=0,且a*a*a*a+m*a*a+1/2a*a*a+ma*a+2a=3求m的值 2a(m)+2=a(m+1)+a(m-1),求{an}解析式 若a^2m-1*a^m+2=a^7则m的值是 若a^2m+1×a^m+1=a^7,则m的值为 已知：a^m=2 a^n=3 求a^m+1 a^n+3 a^m+n a^m+n+2 A^m+1*a^m+n=a^8且a^m*(a^-2)^n=a求m、n的值 (4a-1)/[(a+2)(a-1)]=m/(a+2)+n/(a-1),求m,n的值 4a-1/(a+1)(a-1)=m/(a+2)+n/(a-1),则m+n= M=a*a-3a=2,N=(a+1)(a-5),判断M,N的大小 1)已知a^3·a^m·a^2m+1=a^25,求m的值 已知a^3*a^m*a^2m+1=a^25,求(m-8)^2010的值 a^m+1×a^3-2a^m×a^4-3a^2×a^m+2,第一采用!