求大师解决,对的加赏.1.将24a²b²-6ab分解因式时,应提取公因式是2.把多项式x²(y-1)+x(1-y)分解因式等于3.分解因式:a(x-y)²-b(y-x)²=4.分解因式:a²(x-y)³-b(y-x)²=
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求大师解决,对的加赏.1.将24a²b²-6ab分解因式时,应提取公因式是2.把多项式x²(y-1)+x(1-y)分解因式等于3.分解因式:a(x-y)²-b(y-x)²=4.分解因式:a²(x-y)³-b(y-x)²=
求大师解决,对的加赏.
1.将24a²b²-6ab分解因式时,应提取公因式是
2.把多项式x²(y-1)+x(1-y)分解因式等于
3.分解因式:a(x-y)²-b(y-x)²=
4.分解因式:a²(x-y)³-b(y-x)²=
5.若x+y=2,xy=3,则x²y+xy²=
6.
1)12x²yz-9x²y²
2)-x²-xy-xz
7.
1)p(x-y)+q(y-x)
2)6(2a+b)(2a-3b)-3(b+2a)
求大师解决,对的加赏.1.将24a²b²-6ab分解因式时,应提取公因式是2.把多项式x²(y-1)+x(1-y)分解因式等于3.分解因式:a(x-y)²-b(y-x)²=4.分解因式:a²(x-y)³-b(y-x)²=
24a²b²-6ab分解因式时,应提取公因式是(6ab)
.把多项式x²(y-1)+x(1-y)=x(y-1)(x-1)
分解因式:a(x-y)²-b(y-x)²
=a(x-y)²-b(x-y)²
=(x-y)²(a-b)
分解因式:a²(x-y)³-b(y-x)²
=a²(x-y)-b(x-y)²
=(x-y(a²-b)
.若x+y=2①
xy=3②
①×②
(x+y)xy=x²y+xy²
∴x²y+xy²
=2×3
=6
6分解因式(求过程)
1)12x²yz-9x²y²
=3x²y(4z-3y)
2)-x²-xy-xz
=-x(x+y+z)
7.分解因式(求过程)
1)p(x-y)+q(y-x)
=p(x-y)-q(x-y)
=(x-y)(p-q)
2)6(2a+b)(2a-3b)-3(b+2a)
=6(2a+b)(2a-3b)-3(2a+b)
=3(2a+b)[2(2a-3b-1)
=3(2a+b)(4a-6b-1)
1.6ab
2.x(x-1)(y-1)
3.(x-y)^2(b-a)
4.(x-y)^2[a^2(x-y)+b]
5.6
6.3x^2y(4z-y)
-x(x+y+z)
7.(x-y)(p-q)
3(2a+b)(4a-6b-3)
1、6ab
2、x(y-1)(x-1)
3、(a-b)(x-y)²
4、(x-y)²[a²(x-y)-b]
5、6
6、
1)原式=3x²y(4z-3y)
2)原式=-x(x+y+z)
7、
1)原式=p(x-y)-q(x-y)=(x-y)(p-q)
2)原式=3(2a+b)(4a-6b-1)