已知x-2y=0,求y/(x^2-y^2)除以1/(x-y)的值
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已知x-2y=0,求y/(x^2-y^2)除以1/(x-y)的值已知x-2y=0,求y/(x^2-y^2)除以1/(x-y)的值已知x-2y=0,求y/(x^2-y^2)除以1/(x-y)的值=1/3
已知x-2y=0,求y/(x^2-y^2)除以1/(x-y)的值
已知x-2y=0,求y/(x^2-y^2)除以1/(x-y)的值
已知x-2y=0,求y/(x^2-y^2)除以1/(x-y)的值
=1/3
原式=y(x-y)/(x+y)(x-y)=y/(x+y)=y/(2y+y)=y/3y=1/3
x-2y=0推出X=2Y...然后带进去就好了哦..
1/3
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