求不定积分 ∫ (1-Inx)/(x-Inx)^2 dx
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求不定积分∫(1-Inx)/(x-Inx)^2dx求不定积分∫(1-Inx)/(x-Inx)^2dx求不定积分∫(1-Inx)/(x-Inx)^2dx∫(1-Inx)/(x-Inx)^2dx=∫(1-
求不定积分 ∫ (1-Inx)/(x-Inx)^2 dx
求不定积分 ∫ (1-Inx)/(x-Inx)^2 dx
求不定积分 ∫ (1-Inx)/(x-Inx)^2 dx
∫(1-Inx)/(x-Inx)^2 dx
= ∫(1-Inx)/[x²(1-Inx/x)²] dx
= ∫[1/(1-Inx/x)²]*(1-Inx)/x²dx
= ∫[1/(1-Inx/x)²]d(lnx/x)
= -∫[1/(1-Inx/x)²d(1-lnx/x)
=1/(1-Inx/x) + c =x/(x-lnx) + c
答案是:-x/(x-Inx)+C
采用分部积分法,详细看图:
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