(sin²a-sin²b)/(sina·cosa-sinb·cosb) 如何化简,

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(sin²a-sin²b)/(sina·cosa-sinb·cosb)如何化简,(sin²a-sin²b)/(sina·cosa-sinb·cosb)如何化简,

(sin²a-sin²b)/(sina·cosa-sinb·cosb) 如何化简,
(sin²a-sin²b)/(sina·cosa-sinb·cosb) 如何化简,

(sin²a-sin²b)/(sina·cosa-sinb·cosb) 如何化简,
(sin²a-sin²b)/(sina·cosa-sinb·cosb)
=[(1-cos2a)/2-(1-cos2b)/2]/[(sin2a)/2-(sin2b)/2]
=(cos2b-cos2a)/(sin2a-sin2b)
【cos2x=1-2sinx^2 sin2x=sinxcosx】