但是是英文Assume that the volume discounts in Table 1 apply only to that portion of the volume in eachinterval.\x05\x05\x05For instance,the discounted price for a $4,000 purchase would be computed as follows:300 + 0.97(700) + 0.95(2,000) + 0.93(

但是是英文Assume that the volume discounts in Table 1 apply only to that portion of the volume in eachinterval.\x05\x05\x05For instance,the discounted price for a $4,000 purchase would be computed as follows:300 + 0.97(700) + 0.95(2,000) + 0.93(
但是是英文
Assume that the volume discounts in Table 1 apply only to that portion of the volume in each
interval.
\x05\x05\x05
For instance,the discounted price for a $4,000 purchase would be computed as follows:
300 + 0.97(700) + 0.95(2,000) + 0.93(1,000) = 3,809
\x05\x05\x05
1.If x is the volume of a purchase before the discount is applied,then write a piecewise definition
for the discounted price P (x) of this purchase.
\x05\x05
2.Use one sided limits to investigate the limit of P(x) as x approaches $1,000.Also,as x
approaches $3,000.
3.Compare this discount method with the one in Question 1.Does one always produce a lower
price than the other?Discuss.(In your discussion you should include a graph of both P(x)
and D(x).)
最好是有解题步骤的

但是是英文Assume that the volume discounts in Table 1 apply only to that portion of the volume in eachinterval.\x05\x05\x05For instance,the discounted price for a $4,000 purchase would be computed as follows:300 + 0.97(700) + 0.95(2,000) + 0.93(

1. If x≤$300,then D(x)=x;

   If $300<x≤$1000,then D(x)=0.97x;

   If $1000<x≤$3000,then D(x)=0.95x;

   If $3000<x≤$4000,then D(x)=0.93x;

2.       limit      P(x) =300+ 0.97*700=979

       x→$1,000

          limit     P(x) =300+ 0.97*700+ 0.95*2, 000=2879

       x→$3,000

3. no.