丨a-2丨+(6+1)²=0,求5ab²-[2a²b-(4ab²-2a²b)]

丨a-2丨+(6+1)²=0,求5ab²-[2a²b-(4ab²-2a²b)]
丨a-2丨+(6+1)²=0,求5ab²-[2a²b-(4ab²-2a²b)]

丨a-2丨+(6+1)²=0,求5ab²-[2a²b-(4ab²-2a²b)]
丨a-2丨+(6+1)²=0,
a-2=0;
a=2;
b+1=0;
b=-1;
求5ab²-[2a²b-(4ab²-2a²b)]
=5ab²-2a²b+4ab²-2a²b
=9ab²-4a²b
=9×2×1-4×4×(-1)
=18+16
=34;
很高兴为您解答,skyhunter002为您答疑解惑
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因为丨a-2丨≥0,(6+1)²≥0
所以要使丨a-2丨+(6+1)²=0
则丨a-2丨=0,解得a=2;
且(b+1)²=0,解得b=-1.
5ab²-[2a²b-(4ab²-2a²b)]
=5ab²-(2a²b-4ab²+2a²b)
=5...

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因为丨a-2丨≥0,(6+1)²≥0
所以要使丨a-2丨+(6+1)²=0
则丨a-2丨=0,解得a=2;
且(b+1)²=0,解得b=-1.
5ab²-[2a²b-(4ab²-2a²b)]
=5ab²-(2a²b-4ab²+2a²b)
=5ab²-2a²b+4ab²-2a²b
=9ab²-4a²b
=9×2×(-1)²-4×2²×(-1)
=18+16
=34
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如果本题有什么不明白欢迎追问
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