证明lim(x→0+)x[1/x]=1

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证明lim(x→0+)x[1/x]=1证明lim(x→0+)x[1/x]=1证明lim(x→0+)x[1/x]=1因为1/x1/x

证明lim(x→0+)x[1/x]=1
证明lim(x→0+)x[1/x]=1

证明lim(x→0+)x[1/x]=1
因为1/x

1/x<=[1/x]<1+1/x,1<=x[1/x]