怎样求当趋向无穷时y=(x²+1)/(x²-1)½的极限?

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怎样求当趋向无穷时y=(x²+1)/(x²-1)½的极限?怎样求当趋向无穷时y=(x²+1)/(x²-1)½的极限?怎样求当趋向无穷时y=(

怎样求当趋向无穷时y=(x²+1)/(x²-1)½的极限?
怎样求当趋向无穷时y=(x²+1)/(x²-1)½的极限?

怎样求当趋向无穷时y=(x²+1)/(x²-1)½的极限?
x→+∞lim y=(x²+1)/(x²-1)½=x→+∞limx=+∞
是不是题抄错了?y=(x+1)/(x²-1)½
如果是:
x→+∞lim y=(x+1)/(x²-1)½=x→+∞lim [(x+1)/(x-1)]½ =1½ =1