-1+3+(-5)+7+(-9)+...+2003+(-2005)=?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/17 14:29:38
-1+3+(-5)+7+(-9)+...+2003+(-2005)=?-1+3+(-5)+7+(-9)+...+2003+(-2005)=?-1+3+(-5)+7+(-9)+...+2003+(-20
-1+3+(-5)+7+(-9)+...+2003+(-2005)=?
-1+3+(-5)+7+(-9)+...+2003+(-2005)=?
-1+3+(-5)+7+(-9)+...+2003+(-2005)=?
从第二项起两个两个配对
原始=-1+(-2)*501=-1003
-1
24点 (1)1 1 9 8 (2)9 9 5 7 (3)9 9 9 7
(5/12-7/9-2/3)/(-1/36)
(-5)-(+3)+(-9)-(-7)+2/1=?
1/(1*3*5)+1/(3*5*7)+1/(5*7*9)+1/(7*9*11).+(25*27*29)
简便运算 (1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/7+1/9)*(1/3+1/5+1/7)
(1-3/2*4)*(1-3/3*5)*...*(1-3/7*9)
简算(5/9×7/10-1/3)×6/5
1/(1×3×5)+1/(3×5×7)+1/(5×7×9)+1/(7×9×11)+...+1/(2001×2003×2005)=?
数学题找规律“?”是什么数字:(1,3)、(5,9)、(7,13)、(9,)
算术题,(1+1/3+1/5+1/7)×(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)×(1/3+1/5+1/7)
数奥题(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7)求(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7)的简便算法要求:
9()2()7()8()()()()4()()9()6()1 3()5()()()()24()()8 5()()1()()8 9 4()1 6 7()()1()()3 6()()88()()()()2()3 6()5
简便计算题1/3+4/(3*5)+6/(3*5*7)+8/(3*5*7*9)+10/(3*5*7*9*11)+1/(3*5*7*9*11)
(9/7+3/1-5/4)×45怎样算
1+3+5+7+9……+2015=()
1,2,3,8,5,32,7,( ),9,128
数学简便计算:8.8-7/9-(0.8+7/9) 1/5x27+3/5x41
-9*(-11)-12*(-8) (1/3-5/7-2/5)*10536*(-19 17/18) -5*7 1/3 +12*(-7 1/3)