x2-x-y2-y 解法：=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)后半部的解法（x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
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x2-x-y2-y解法：=(x2-y2)-(x+y)=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)后半部的解法（x+y)(x-y)-(x+y)=(x+y)(x-y-1)怎么得的x2-x-
x2-x-y2-y 解法：=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)后半部的解法（x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
x2-x-y2-y 解法：=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)
后半部的解法（x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
x2-x-y2-y 解法：=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)后半部的解法（x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
哥!你那个是x方y方吧!
有这么个公式 x方-y方=（x+y）(x-y)
所以得到了（x+y)(x-y)-(x+y)
这时候提取公因式（x+y)就得到了（x+y)(x-y-1)
提出（x+y）,得（x+y)(x-y)-(x+y) =（x+y）（x-y-1)
（x+y)(x-y)-(x+y)这个式子提取（x+y)后，减号左边得到的是(x-y)。右边是1。结果就是(x+y)(x-y-1)
把 （x+y)看做整体提取公因式
（x+y)(x-y)-(x+y)
=(x+y)(x-y)-(x+y)×1
=(x+y)(x-y-1)
二元二次方程组：(X2+X2/2=Y2 X/2+X+Y=6)解法
x2+x+y2/x+y
x2+y2=208(x-y)
(x-y)(x2+xy+y2)
(x+y)(x2-xy+y2)
X2y2-x2-y2+1 =x2(y2-1)-(y2-1) =(y2-1)(x2-1) =(y+1)(y-1)(x+1)(x-1) 中的=x2(y2-1)-(y2-1) =(y2-1)(x2-1是怎么算出来的?
x2-2xy+y2=4 x2+y2-x-y=6 解不等式x2-2xy+y2=4 x2+y2-x-y=6 解不等式
已知x,y满足（x2+y2）(x2+y2-1)=2,则x2+y2的值为多少?x2,y2表示x和y的平方
2010.09.已知x、y为实数,且(x2+y2)(x2+y2+1)=20,求x2+y2的值
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x2+y2+x+y=18 x2+y2-2x-4x=24 解方程组
y=x+√(1-x2) y2=x2+(1-x2)+2x√(1-x2)
我做对了吗.x2(x-y)+y2(y-x)= x2(x-y)-y2(x-y)=x2-y2=(x+y）（x-y）
解方程组①x2-y2=3x+3y②x2-xy+y2=27
方程组 x2+y2+x+y=18 x2+xy+y2=19
已知x2-y2=20,x+y=4,则x2+y2的值是多少?
x2+y2=1和x2+y2-4x+2y=4解这组方程,
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