计算 2+x+3/x-1*x^2-2x+1/x^2+6x+9
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/06 00:41:15
计算2+x+3/x-1*x^2-2x+1/x^2+6x+9计算2+x+3/x-1*x^2-2x+1/x^2+6x+9计算2+x+3/x-1*x^2-2x+1/x^2+6x+92+[(x+3)/(x-1
计算 2+x+3/x-1*x^2-2x+1/x^2+6x+9
计算 2+x+3/x-1*x^2-2x+1/x^2+6x+9
计算 2+x+3/x-1*x^2-2x+1/x^2+6x+9
2+[(x+3)/(x-1)][(x²-2x+1)/(x²+6x+9)]
=2+[(x+3)/(x-1)][(x-1)²/(x+3)²]
=2+(x-1)/(x+3)
=[2(x+3)+(x-1)]/(x+3)
=(3x+5)/(x+3)
请点击下面的【选为满意回答】按钮.
2+x+3/x-1*x^2-2x+1/x^2+6x+9
=11+5x+3/x-x^2
计算：1-2x+x^2/x-x^3*xy+x^2y/x-x^2
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
计算：x/(x-1)-(x+3)/(x^-1)*(x^2+2x+1)/(x+3)
计算(x+1)(x+2)(x+3)(x+4)
计算：（x+1)(x-2)(x-3)(x-6)
计算 x(x+3)-(x-1)(x-2）
如何计算 (x+1)(x+2)(x+3)(x+4)
计算(X-1)(X-2)(X-3)(X-4)
(x-1)(x-2)(x-3)(x-4)-24计算
计算：x(x^2+x-1)-(x^2-x+1)
x/x-3-5x/x^2-x-6计算
计算:x/x-2 - 5x/x²-x-6计算:x/x-3 - 5x/x²-x-6
x(x-2)(2x-3)计算
计算： (x+3)(x²-x-2)
计算 (x+3)(x²-x-2)
2x*4x-3x计算
计算:[(x+2)/(x+3) - (x+1)/(x+2) + (x+4)/(x+5) - (x+3)/(x+4) / (x^2 + 7x + 13)/(x^2 + 8x + 15)
2x/x-1+1/x+3-3x+5/x^2+2x-3计算,