-7+x+2x^2+6x^3+4x^4=0没有抄错题啊，就是这个四次方程

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-7+x+2x^2+6x^3+4x^4=0没有抄错题啊，就是这个四次方程-7+x+2x^2+6x^3+4x^4=0没有抄错题啊，就是这个四次方程-7+x+2x^2+6x^3+4x^4=0没有抄错题啊，

-7+x+2x^2+6x^3+4x^4=0没有抄错题啊，就是这个四次方程
-7+x+2x^2+6x^3+4x^4=0
没有抄错题啊，就是这个四次方程

-7+x+2x^2+6x^3+4x^4=0没有抄错题啊，就是这个四次方程
用数学软件Solve[4 x^4 + 6 x^3 + 2 x^2 + x - 7 == 0,x]：{{x -> -(3/8) +
1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] -
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) - 19/(
32 Sqrt[11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) -
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))},{x -> -(3/
8) + 1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] +
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) - 19/(
32 Sqrt[11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) -
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))},{x -> -(3/
8) - 1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] -
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) + 19/(
32 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))},{x -> -(3/8) -
1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] +
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) + 19/(
32 Sqrt[11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) -
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))}}
这是mathematica的运行结果

强烈怀疑你抄错题了。。。否则答案是个很复杂的数。。恩

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该多元四次方程用一般的人工计算的办法是非常麻烦的！需要借z助mathmatica,matlab软件进行计算我算了一下，运行结果为：{{x -> -(3/8) +
1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] -
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) - 19/(
32 Sqrt[11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) -
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))}, {x -> -(3/
8) + 1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] +
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) - 19/(
32 Sqrt[11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) -
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))}, {x -> -(3/
8) - 1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] -
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) + 19/(
32 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))}, {x -> -(3/8) -
1/2 Sqrt[
11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) - 175/(
6 (2 (-689 + 9 Sqrt[138191]))^(1/3))] +
1/2 \[Sqrt](11/24 - (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) +
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3)) + 19/(
32 Sqrt[11/48 + (-689 + 9 Sqrt[138191])^(1/3)/(6 2^(2/3)) -
175/(6 (2 (-689 + 9 Sqrt[138191]))^(1/3))]))}}

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*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? 2x+3x+4x+5x+x+6x+7x=100 x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=? 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8 好多年没有用过过数学公式了想不起来怎么算了想知道 X值是多少难倒爱因斯坦的九宫格X 7 X | X 8 1 | X X X |X X X | X 4 X | 7 5 9 |X X 5 | 7 X 9 | X 1 4 |5 X X | X X 8 | 3 9 X |3 9 6 | 4 X 7 | X X 2 |X 8 7 | 9 X X | X X X |4 X X | 6 X 5 | X X X | X X 4 | X X 1 |2 X X | X X X | X X X | X 3 X | X X X |X 6 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^+x^6+x^7+x^8的值如果1+x+x^2+x^3=0,求x+x^2+X^3+x^4+x^5+x^6+x^7+x^8的值, 已知x=2π+1求 |x-1|+|x-2|+|x-3|+|x-4|+|x-5|+|x-6|+|x-7|+|x-8|+|x-9|+|x-10| 已知x=2π+1.求(X-1)+(X-2)+(X-3)+(X-4)+(X-5)+(X-6)+(X-7)+(X-8)+(X-9)+(X-10) 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11=17.7这个方程怎么样求解? 解方程(x-2)/(x-3)-(x-3)/(x-4)=(x-5)/(x-6)-(x-6)/(x-7) (x-5)/(x/7)+(x-2)/(x-4)=(x-3)/(x-5)+(x-4)/(x-6) 解方程 x+2/x+1+x+8/x+7=x+6/x+5+x+4/x+3 (x-1)(x-2)(x-3)(x-4)=(x+5)(x+6)(x+7)求X等于几? 因式分解 x^8+x^7+x^6+x^5+x^4+x^3+x^2+x=? x-2/x-1+x-8/x-7=x-4/x-3+x-6/x-5