sin(a-π/3)=1/3,则cos(π/6+a)的值为___
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sin(a-π/3)=1/3,则cos(π/6+a)的值为___sin(a-π/3)=1/3,则cos(π/6+a)的值为___sin(a-π/3)=1/3,则cos(π/6+a)的值为___cos(
sin(a-π/3)=1/3,则cos(π/6+a)的值为___
sin(a-π/3)=1/3,则cos(π/6+a)的值为___
sin(a-π/3)=1/3,则cos(π/6+a)的值为___
cos(π/6+a)=sin[π/2-(π/6+a)]=sin(π/3-a)= - sin(a-π/3)= -1/3
填:-1/3 cos(π/6+a) =cos[π/2-(π/3-a)] =sin(π/3-a) =-sin(a-π/3) =-1/3
已知 sin a-cos a=1/2,则 sin^3 a-cos^3 a
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
设角a=-35π/6,则2sin(π+α)cos(π-α)-cos(π+α)/ 1+sin^2α+sin(π-α)-cos^2(π+α)sina=sin(-35π/6)=sin(-6π+π/6)=1/2 cosα=根号3/22sin(π+α)cos(π-α)-cos(π+α)/ [1+sin^2α+sin(π-α)-cos^2(π+α)]=2(-sinα)(-cosα)+cosα/[1+sin²
tana=m则sin(a+3π)+cos(π+a)/sin(-a)-cos(π+a)=?
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求证1/sin^2a+3/cos^2a>=4+2根号下31/sin²a +3/cos²a=(sin²a+cos²a)/sin²a +3(sin²a+cos²a)/cos²a=1+cos²a/sin²a+3+3sin²a/cos²a=4+cos²a/sin²a+3sin²a/cos²a≥4+2√[(cos
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已知sin(a-π)=2cos(2π-a),求(sin(π-a)+5cos(2π-a))/(3cos(π-a)-sin(-a))的值.
sin(a-π)=2cos(2π-a).求3cos(π-a)-sin(-a)/sin(π-a)+5cos(2π-a)
若sin(π-a)=2cos(2π-a),求sin(π-a)+5cos(2π-a)/3cos(π-a)-sin(-a)的值
已知sin(a-π)=2cos(2π-a),求sin(π-a)+5cos(2π-a)/3cos(π-a)+sin(-a)的值.