已知x,y满足4x²+y²-4x-6y+10=0

已知x,y满足4x²+y²-4x-6y+10=0
已知x,y满足4x²+y²-4x-6y+10=0

已知x,y满足4x²+y²-4x-6y+10=0
4x²+y²-4x-6y+10=0
(2x-1)²+(y-3)²=0；
(2x-1)²>=0,(y-3)²>=0,
若等式成立,(2x-1)²=0,x=1/2;(y-3)²=0,y=3;
原式=[(2/3)x*3√x+y²*1/y²*√(xy)]-[x²*1/x*√x-5x*1/x*√(xy)]
=2x√x+√(xy)-x√x+5√(xy)
=x√x+6√(xy)
=(1/2)√(1/2)+6√(3/2)
=(1/4)√(2)+6*1/2*√(6)
=(1/4)√(2)+3√(6)