(2+1)(2^2+1)(2^4+1)(2^8+1).(2^2048+1)=?

来源：学生作业帮助网编辑：六六作业网时间：2024/12/23 15:48:51

(2+1)(2^2+1)(2^4+1)(2^8+1).(2^2048+1)=?(2+1)(2^2+1)(2^4+1)(2^8+1).(2^2048+1)=?(2+1)(2^2+1)(2^4+1)(2^

(2+1)(2^2+1)(2^4+1)(2^8+1).(2^2048+1)=?
(2+1)(2^2+1)(2^4+1)(2^8+1).(2^2048+1)=?

(2+1)(2^2+1)(2^4+1)(2^8+1).(2^2048+1)=?
(2+1)(2的平方+1)(2的4次方+1)(2的8次方+1).(2的2048+1)
＝（2－1）(2+1)(2的平方+1)(2的4次方+1)(2的8次方+1).(2的2048+1)
＝(2的平方-1)(2的平方+1)(2的4次方+1)(2的8次方+1).(2的2048+1)
＝.＝(2的4096次方-1)
原式=(2-1)（2+1)(2^2+1)(2^4+1)(2^8+1).(2^2048+1)
=(2^2-1)(2^2+1))(2^4+1)(2^8+1).(2^2048+1)
然后不停地用平方差公式
=2^4096-1

(2+1)(2^2+1)(2^4+1)(2^8+1)....(2^2048+1)
原式＝（2－1）(2+1)(2^2+1)(2^4+1)(2^8+1)....(2^2048+1)
＝(2＾2－1)(2^2+1)(2^4+1)(2^8+1)...(2^2048+1)
＝(2^4－1)(2^4+1)(2^8+1)...(2^2048+1)
＝(2^8－1)(2^...

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1/2,1/4, (1-1/2^2)(1-1/3^2)(1-1/4^2).(1-1/2009^2), (2+1)({2}^{2}+1)({2}^{4}+1)({2}^{8}+1).({2}^{64}+1)+1 巧算((2^1+1)(2^2+1)(2^4+1)(2^8+1)+1)/2^15 计算(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)+1 计算:(2+1)(2^2+1)(2^4+1)(2^8+1)-2^16.计算：(2+1)(2^2+1)(2^4+1)(2^8+1)-2^16. [(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)] (1-1/2^2)*(1-1/3^2)*(1-1/4^2)*.*(1-1/2002^2)*(1-1/2003^2) (1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)(1+1/2^16), 1,2,4,4,1,( ) (2^1+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1 (2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1） (2+1)(2-1)(2^2+1)(2^4+1).(2^8+1)化简 (1+2)*(1+2^2)*(1+2^4)*(1+2^8)*(1+2^16) 化简(1+2)(1+2^2)(1+2^4)(1+2^8)(1+2^16) 化简(2+1)(2^2+1)(2^4+1)(2^8+1)…(2^256+1) (2-1)(2+1)(2^2+1)(2^4)...(2^64+1)+1=? (2+1)(2^2+1)(2^4+1)(2^8+1)……(2^1024+1)