化简求值.（a-2/a²+2a-a-1/a²+4a+4）÷a-4/a+2,其中a满足a²+2a-1=0.

化简求值.（a-2/a²+2a-a-1/a²+4a+4）÷a-4/a+2,其中a满足a²+2a-1=0.
化简求值.
（a-2/a²+2a-a-1/a²+4a+4）÷a-4/a+2,其中a满足a²+2a-1=0.

化简求值.（a-2/a²+2a-a-1/a²+4a+4）÷a-4/a+2,其中a满足a²+2a-1=0.
因为a^2+2a-1=0,
所以a^2+2a=1,
所以[(a-2)/(a^2+2a)-(a-1)/(a^2+4a+4)]/[(a-4)/(a+2)
=[(a-2)/a(a+2)-(a-1)/(a+2)^2]*[(a+2)/(a-4)]
=[(a-2)(a+2)/a(a+2)^2-a(a-1)/a(a+2)^2]*[(a+2)/(a-4)]
=[(a^2-4-a^2+a)/a(a+2)^2]*[(a+2)/(a-4)]
=[(a-4)/a(a+2)^2]*[(a+2)/(a-4)]
=1/a(a+2)
=1/(a^2+2a)
=1/1
=1.

你的题目不好理解，分数线的前后部分怎么区分啊？