(x^2+sin^2x)/(x^2+1)sec^2xdx的不定积分我算的是x-arctanx+c答案是x-arccotx+c

化简(sin x+cos x-1)(sin x-cos x+1)/sin 2x x*（1+sin^2 x )/sin^2x 不定积分 傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si 化简(sin^2 x/sin x-cosx)-(sin x+cosx/tan^2 x-1) sin(x^2)/sin^2x 求导 (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x 化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x (1+tan(x))/sin(2x)不定积分 ((sin x) -1)^2 对x求导 （sin(1+2x)/x)的导数 求极限 lim sin(x^2 * sin (1/x))/x x->0求极限 lim sin(x^2 * sin (1/x))/x x->0 求极限 （（sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1 ∫sin^2x/(1+sin^2x )dx求解, 求不定积分【sin(x)^5 + sin(x)^3】^(1/2) 1-2sinx*sin(60+x)sin(60-x) 化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x 化简sin(-2x) lim(x(sin)^2)