若|5x+2y-12|+（3x-2y-6）平方=0,则x+2y=?

[2(x-y)^5-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2[2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2 化简(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90) 2(2x+3y)(3x+2y)-(6x-y)(2x-5y) [12(x+y)^3+3(x+y)(x-y)^2]÷6(x+y) x+y/2+x-y/6=5 2(x+y)-3(x-y)=-2 若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于 因式分解x次方-y次方+5x-y+6【x-y+2】【x+y+3】 6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5 5/12[-3/4(x-y)^3]*(x+y)^2*(-x-y)^3*5/6(y-x)^2 若5x+3y=3x+4y=x+2y+6,则x+y=___ 解方程组：x+y/2+x-y/3=6 4(x+y)-5(x-y)=12 2(x-2y)²-7(x-2y)³+3(2y-x)²+(2y-x)³合并同类项 这个式子2（x-2y)²-7（x-2y)³+3(2y-x)²-(2y-x)³=2（x-2y)²-7（x-2y)³+3(x-2y)²+(x-2y)³=5(x-2y)²-6(x-2y)³=(x-2y)²(5-6x+12y) 若|x-2y+6|+(x+y+12)的2次方,求4x+5y 6x^4y^3+12x^3y^4-24x^2y^5因式分解 化简:5(x-y)+2(x+y)-3(x-y) (1)x^2*x^8+x^13/x^3 (2)a^19/a^12/a^3 (3) (x-2y)^5/(2y-x)^3 (4)(x-y)^5/(x-y) (5)(x-y)^6/(y-x)^4 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)