1/x2-3x+2+1/x2-5x+6+1/x2-7+1/x2-7x+12-4/x2-6x+5 有多少种写多少种解法,
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1/x2-3x+2+1/x2-5x+6+1/x2-7+1/x2-7x+12-4/x2-6x+5有多少种写多少种解法,1/x2-3x+2+1/x2-5x+6+1/x2-7+1/x2-7x+12-4/x2
1/x2-3x+2+1/x2-5x+6+1/x2-7+1/x2-7x+12-4/x2-6x+5 有多少种写多少种解法,
1/x2-3x+2+1/x2-5x+6+1/x2-7+1/x2-7x+12-4/x2-6x+5 有多少种写多少种解法,
1/x2-3x+2+1/x2-5x+6+1/x2-7+1/x2-7x+12-4/x2-6x+5 有多少种写多少种解法,
=1/(x-2)(x-1)+1/(x-2)(x-3)+1/(x-3)(x-4)-4/(x-1)(x-5) 帮你删除了 1/x2-7
=1/(x-2)-1/(x-1)+1/(x-3)-1/(x-2)+1/(x-4)-1/(x-3)-[1/(x-5)-1/(x-1)]
=1/(x-5)
计算:x2-5x+6/x2-4x+3 + x2-4x+3/x2-2x+1 + x2-3x-4/1-x2
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=4/21x2是x的平方
x2-4x+3分之x2-5x+6+s2-2x+1分之x2-4x+3+1-x2分之x2-3x-4的过程
x2-1/x2-5x+6
6x2-[-3x2-(x-1)] 化简
(-2x)*(x2-5x+6)-4x(2x2-3x+1)
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x2+11x-708等会就要 再次坐等
化简计算~1/(x2-5x+6) - 1/(4x-x2-3) - 1/(3x-x2-2)
6x+2x2次方一3x+x2次方+1,其中x=一5
解方程:X2--1/8(X2+2X)+X2+2X/3(X2--1)=11
解方程 2/(x2-x)+6/(1-x2)=7/(x2+x)x2为的平方
2(x2+6x+1)2+5(x2+1)(x2+6x+1)+2(x2+1)2 分解因式
x2+3x+9/x2-27+6x/9x-x2-x-1/6+2x 化简
化简x2+3x+9/x2-27+6x/9x-x2-x-1/6+2x
已知x2+5x-4=0,求x3+6x2+x+2的值已知x2+x-1=0,求x3+2x2+3的值
7/x2+x+1/x2-x=6/x2-1
3/x2 -3x+2-1/x-2=1/x2 -x+4/x2 -2x