(x+y)^2-4(x+y)=5 (x-y)^2-x(x-y)=3 解二元二次方程组 要过程
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/08 11:09:40
(x+y)^2-4(x+y)=5(x-y)^2-x(x-y)=3解二元二次方程组要过程(x+y)^2-4(x+y)=5(x-y)^2-x(x-y)=3解二元二次方程组要过程(x+y)^2-4(x+y)
(x+y)^2-4(x+y)=5 (x-y)^2-x(x-y)=3 解二元二次方程组 要过程
(x+y)^2-4(x+y)=5 (x-y)^2-x(x-y)=3 解二元二次方程组 要过程
(x+y)^2-4(x+y)=5 (x-y)^2-x(x-y)=3 解二元二次方程组 要过程
不知道
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
x*x+2x+y*y-4y+5=0 x= y=
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?
化简求值:2(x+y)(x-2y)-2x(x+y),其中x、y满足x^2+y^2-2x+4y=-5
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
5x-4y(y-x)=?
4x+2y-5x-y
(x-4y)(2x+y)=
因式分解(x-2y)(x-3y)+(x-4y)(x-5y)+(x-3y)(x-5y)+(x-2y)(x-4y)
3X=5Y (X+Y)*3X=(2Y+X)*4+2*2
x*x+y*y-2x+4y+5=0求x,