2/5X-1/3Y+1=0 2X+2Y=7
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2/5X-1/3Y+1=02X+2Y=72/5X-1/3Y+1=02X+2Y=72/5X-1/3Y+1=02X+2Y=7emilytbaw2/5x-1/3y+1=02x+2y=7整理,得6x-5y+1
2/5X-1/3Y+1=0 2X+2Y=7
2/5X-1/3Y+1=0 2X+2Y=7
2/5X-1/3Y+1=0 2X+2Y=7
emilytbaw
2/5x-1/3y+1=0
2x+2y=7
整理,得
6x-5y+15=0 ①(方程两边同时乘以15)
2x+2y=7 ②
②×3,得
6x+6y=21 ③
③-①,得
11y=36
解得y=36/11
把y=36/11代入②中,得
2x+2×(36/11)=7
2x=5/11
解得x=5/22
∴这个二元一次方程组的解是:x=5/22,y=36/11
用加减消元法:①×15-②×3消去x,得y=36/11. 将y代回①式或②式,得x=5/22.
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