lim(1/(x+1)+1/(x^2-1)) x->-1 求极限
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/23 16:24:34
lim(1/(x+1)+1/(x^2-1))x->-1求极限lim(1/(x+1)+1/(x^2-1))x->-1求极限lim(1/(x+1)+1/(x^2-1))x->-1求极限原式=lim(x->
lim(1/(x+1)+1/(x^2-1)) x->-1 求极限
lim(1/(x+1)+1/(x^2-1)) x->-1 求极限
lim(1/(x+1)+1/(x^2-1)) x->-1 求极限
原式=lim(x->-1) [(x-1+1)/(x+1)(x-1)]
=lim(x->-1) [x/(x+1)(x-1)]
因为
lim(x->-1) [(x+1)(x-1)/x]=0
所以
原式=∞.
lim(1-x)^(2/x) x->0
极限：lim(x->2)1/(x-2)
lim(1-(5/x))^x-2
lim(x+e^2x)^(1/sinx)
lim（x-3/x+1）^x lim趋向无穷大
Lim(x>1) x-1/x^2+x-2.计算
lim x→1 x-1/x^2-x
lim(x^2+1/x^2-2x)^x=?
lim(x->无穷大){(2^x-3^x)/2}^(1/x)
Lim [x^2/(x^2-1)]^x (x→∞)
lim x->正无穷大 x ( sqrt(x^2+1)-x )
lim(x->0)((2-x)/(3-x))^1/x
lim(1+x/x)2x (x→∞)
lim(x→0)e^x-x-1/x^2
lim(x+1/x+2)^x=?x趋于无穷
lim(x趋于无穷)(x/1+x)^(x+2)=?
lim[(x-1)/(x+1)]^x
lim (e-(1+x)^(1/x))/x