已知x-3y=0,y≠0,求x²-2xy+y²分之2x+y×（x-y）的值

已知x-3y=0,y≠0,求x²-2xy+y²分之2x+y×（x-y）的值
已知x-3y=0,y≠0,求x²-2xy+y²分之2x+y×（x-y）的值

已知x-3y=0,y≠0,求x²-2xy+y²分之2x+y×（x-y）的值
去求解答（专攻数理化）看,你可以去搜一下找来了原题答案哦,

[2x+y(x-y)]/(x²-2xy+y²)
=[(2x+y)(x-y)]/(x-y)²
=2x+y/(x-y)
∵x-3y=0，x=3y
(6y+y)/(3y-y)=7y/2y=7/2