已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/23 19:15:37
已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+
已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
x^2-3x+1=0
x^2+1=3x
x^2/(x^4+4x^2+1)
=x^2/(x^2+1)^2
=x^2/9x^2
=1/9