已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
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已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+
已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
已知x^2-3x+1=0,则分式x^2/(x^4+4x^2+1)的值为
x^2-3x+1=0
x^2+1=3x
x^2/(x^4+4x^2+1)
=x^2/(x^2+1)^2
=x^2/9x^2
=1/9