换元法 2(x-1)/x+3+6(x+3)/x-1=7
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换元法2(x-1)/x+3+6(x+3)/x-1=7换元法2(x-1)/x+3+6(x+3)/x-1=7换元法2(x-1)/x+3+6(x+3)/x-1=7设t=(x-1)/(x+3)∴原式可换为2t
换元法 2(x-1)/x+3+6(x+3)/x-1=7
换元法 2(x-1)/x+3+6(x+3)/x-1=7
换元法 2(x-1)/x+3+6(x+3)/x-1=7
设t = (x-1) /(x+3)
∴原式可换为 2t +6/t = 7
可解得 t =3/2 或2
当(x-1)/(x+3)=3/2时 可得 x=-11
当(x-1)/(x+3)=2 可得 x=-7
设X-1为Y,则X+3为Y+4
原方程换为2y/(y+4)+6(y+4)/y = 7
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