2[3(5x-1)-8]-7=1

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2[3(5x-1)-8]-7=12[3(5x-1)-8]-7=12[3(5x-1)-8]-7=12[3(5x-1)-8]-7=12[3(5X-1)-8]=7+1;3(5X-1)-8=4;3(5X-1)

2[3(5x-1)-8]-7=1
2[3(5x-1)-8]-7=1

2[3(5x-1)-8]-7=1
2[3(5x-1)-8]-7=1
2[3(5X-1)-8]=7+1;
3(5X-1)-8=4;
3(5X-1)=12;
5X-1=4;
5X=5;
X=1;
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2[3(5x-1)-8]-7=1
2[3(5x-1)-8]=8
[3(5x-1)-8]=4
3(5x-1)=12
5x-1=4
5x=5
x=1

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