用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为

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用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则

用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为
用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为

用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为
设x^2/x+1=y,则原方程可化为
6/y+y=7

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