main() {int a[4][4]={{1,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,1}},i,j,k,t 这道程序是怎么运行的main(){int a[4][4]={{1,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,1}},i,j,k,t;for(i=0;i

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/25 01:38:39
main(){inta[4][4]={{1,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,1}},i,j,k,t这道程序是怎么运行的main(){inta[4][4]={{1,4

main() {int a[4][4]={{1,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,1}},i,j,k,t 这道程序是怎么运行的main(){int a[4][4]={{1,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,1}},i,j,k,t;for(i=0;i
main() {int a[4][4]={{1,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,1}},i,j,k,t 这道程序是怎么运行的
main()
{int a[4][4]={{1,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,1}},i,j,k,t;
for(i=0;i

main() {int a[4][4]={{1,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,1}},i,j,k,t 这道程序是怎么运行的main(){int a[4][4]={{1,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,1}},i,j,k,t;for(i=0;i
先是对矩阵的每列按从小到大排序(应该是选择排序法),然后输出对角元
需要具体解释吗?