若1/x+2/y+3/z=5,3/x+2/y+1/x=7,求1/x+1/y+1/z+19若 1/x + 2/y + 3/z = 5 ,3/x + 2/y + 1/x = 7,求1/x+1/y+1/z+19

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若1/x+2/y+3/z=5,3/x+2/y+1/x=7,求1/x+1/y+1/z+19若1/x+2/y+3/z=5,3/x+2/y+1/x=7,求1/x+1/y+1/z+19若1/x+2/y+3/z

若1/x+2/y+3/z=5,3/x+2/y+1/x=7,求1/x+1/y+1/z+19若 1/x + 2/y + 3/z = 5 ,3/x + 2/y + 1/x = 7,求1/x+1/y+1/z+19
若1/x+2/y+3/z=5,3/x+2/y+1/x=7,求1/x+1/y+1/z+19
若 1/x + 2/y + 3/z = 5 ,3/x + 2/y + 1/x = 7,求1/x+1/y+1/z+19

若1/x+2/y+3/z=5,3/x+2/y+1/x=7,求1/x+1/y+1/z+19若 1/x + 2/y + 3/z = 5 ,3/x + 2/y + 1/x = 7,求1/x+1/y+1/z+19
1/x + 2/y + 3/z = 5 ,
3/x + 2/y + 1/x = 7
两式相加,得4(1/x+1/y+1/z)=12,所以1/x+1/y+1/z=3,所以原式=22

已知a大于1,a+a分之1=根号5