若|X-1/2|+|Y-1/6|=0求X+Y的值
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 23:01:38
若|X-1/2|+|Y-1/6|=0求X+Y的值若|X-1/2|+|Y-1/6|=0求X+Y的值若|X-1/2|+|Y-1/6|=0求X+Y的值绝对值大于等于0,相加等于0,若有一个大于0,则另一个小
若|X-1/2|+|Y-1/6|=0求X+Y的值
若|X-1/2|+|Y-1/6|=0求X+Y的值
若|X-1/2|+|Y-1/6|=0求X+Y的值
绝对值大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立.
所以两个都等于0
所以x-1/2=0,y-1/6=0
x=1/2,y=1/6
所以x+y=2/3
X+Y=1/2+1/6=2/3
由题知x=1/2 y=1/6
x+y=2/3
由题意可得:
X-1/2=0
Y-1/6=0
解得X=1/2,Y=1/6
所以X+Y=2/3
若(x+y)(x+y-1)-2=0,求x+y的值求
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
若x*x+y*y=x+y-1/2,求x,y的值如题
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
计算(1) (x+y)(-x-y)(x+y)² (2) (-1/3x²y³)³(3) 若x²+3x-2=0,求2x³+6x²-4x+2的值
y=6/(2sinx-1) 求值域 y=x+|1/x^2(x>0)求值域.y=x^2+2/x (x>0)求值域
已知x求^2+y^2-6x-8y+25=0求1/x-y /x+y/x^4-y^4
若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
若(-x+6):(x-y):(4x+y)=3:14:1,求x+y
若(-x+6):(x-y):(4x+y)=3:14:1,求x+y
若|x-2y|+|1/2x+2y-6|=0,求x+y的值
若(2x-y-1)2+|x-2y-3|=0,求代数式(2x+y)(2x-y)-(x+2y)(x-2y-1)的值若(2x-y-1)²+|x-2y-3|=0,求代数式(2x+y)(2x-y)-(x+2y)(x-2y-1)的值
若x^5+x^4y+x^4+x+y+1=0,且3x+2y=1,求x,y的值
若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,求(x²+y²)/2-xy的值若x(x-1)-(x²-y)=-6,
若|x-y|+|2x-4|=2x-4且|x+y-1|=0求x,
若|y+5|+(5x+1)2=0,求-3(2x-y)-{7x-[6x+2y-(10x-8y)]-x-2(3x-4y)}的值
若|y+5|+(5x+1)^2=0,求代数式-3(2x-y)-{7x-[6x+2y-(10x-8y)]-x-2(3x-4y)}的值
若|y+5|+(5x+1)^2=0,求-3(2x-y)-{7x-[6x+2y-(10x-8y)]-x-2(3x-4y)}的值