(3a-5b-2c)(-3a-5b+2c)
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(3a-5b-2c)(-3a-5b+2c)(3a-5b-2c)(-3a-5b+2c)(3a-5b-2c)(-3a-5b+2c)(3a-5b-2c)(-3a-5b+2c)=[-5b+(3a-2c)][-
(3a-5b-2c)(-3a-5b+2c)
(3a-5b-2c)(-3a-5b+2c)
(3a-5b-2c)(-3a-5b+2c)
(3a-5b-2c)(-3a-5b+2c)
=[-5b+(3a-2c)][-5b-(3a-2c)]
=(-5b)²-(3a-2c)²
= 25b²-(9a²-12ac+4c²)
=25b²-9a²+12ac-4c²
(3a-5b-2c)(-3a-5b+2c)
=[-5b+(3a-2c)]*[-5b-(3a-2c)]
=25b²-(3a-2c)²
=25b²-9a²-4c²+12ac
2a(a+b-c)-3b(a+b-c)+5c(c-a-b)
化简:7(a-b-c)-5(a+b-c)+3(a-b-c)+(a+b-2)
已知:(a-b)(b-c)(c-a)/(a+b)(b+c)(c+a)=5/132,求a/(a+b)+b/(b+c)+c/(c+a)的值!(请尽快,我有急用,a/(a+b)+b/(b+c)+c/(c+a)=1/2[(a-b)/(a+b)+(b-c)/(b+c)+(c-a)/(c+a)]+3/2 (a-b)/(a+b)+(b-c)/(b+c)+(c-a)/(c+a) 没有错吧...
(a+b-c)^5(a-b-c)^2(c-a-b)^4(c+b-a)^3 计算
分解因式:2a(a+b-c)-3b(a+b-c)+5c(c-a-b)
2a(a+b+c)-3b(a+b+c)+5c(c-a-b)分解因式
2a(a+b+c)-3b(a+b-c)+5c(c-a-b)分解因式
(a-b+c/a+b-c)-(a-2b+3c/b-c+a)+(b-2c/c-a-b)
a-b=5,b-c=3,(c-a)(2b-a-c)=
5a+{3b+[6c-2a-2(a-c)]}-[9a-(7b+c)]
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
5a-{-3b+[6c-2a-(a-c)}-[9a-(7b+c)]
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
计算:5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
初二分式的加减法2a-b-c/(a-b)(a-c)+ 2b-c-a/(b-c)(b-a)+ 2c-b-a/(c-b)(c-a)3a-6b/a+b- 5a-6b/a-b- 4a-5b/a+b+ 7a-8b/b-a注:有空格的地方是下一个分式
已知:(a+b)/(a-b)=(b+c)/2(b-c)=(c+a)/3(c-a),求证:8a+9b+5c=0
已知:(A+B)/(A-B)=(B+C)/2(B-C)=(C+A)/3(C-A).求证:8A+9B+5C=0
已知a+b/a-b=b+c/2(b-c)=c+a/3(c-a),求证:8a+9b+5c=0