(2/1+a)-(a-2/a-1)÷(a²-2a/a²-2a+1)等于多少
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(2/1+a)-(a-2/a-1)÷(a²-2a/a²-2a+1)等于多少(2/1+a)-(a-2/a-1)÷(a²-2a/a²-2a+1)等于多少(2/1+a
(2/1+a)-(a-2/a-1)÷(a²-2a/a²-2a+1)等于多少
(2/1+a)-(a-2/a-1)÷(a²-2a/a²-2a+1)等于多少
(2/1+a)-(a-2/a-1)÷(a²-2a/a²-2a+1)等于多少
2/1是二分之一嘛?
如果是的话
.(2/1+a)-(a-2/a-1)÷(a²-2a/a²-2a+1)
=(2/1+a-a+2/a+1)÷(a²-2/a-2a+1)
=[2/(1+a+2)×2]÷[(a²-2a+1)-2/a×2]
=(1+a+2)÷[2(a-1)²-a]
=(a+3)÷[2(a-1)²-a]
貌似就是酱紫了吧
(2/1+a)-(a-2)/(a-1)x(a-1)x(a-1)/a(a-2)
(2/1+a)-(a-1)/a
(-a^2+2a+1)/a(1+a)
(2/1+a)-(a-2/a-1)÷(a²-2a/a²-2a+1)题目中的括号位置准确吗?
【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a-a a=[ ] [4]a-a=a+a a=[ ]
(a 1)(a 2)(a 3)(a
(a+2)(a+1)-a(a-3)
(1-16a×a×a×a)÷(4a×a+1)÷(2a+1)²
(1-16a×a×a×a)÷(4a×a+1)÷(2a+1)
[(a/a-2)-(a/a+2)]÷4a/2-a,其中a=-1/2
[a-a/(a+1)]÷(a²-2a)/(a²-4)×(a+1)/(a²+4a+4)
a-1/a+2
1-a/-2-a
-2×a×1/a
先化简,再求值:(a-1/a-a-2/a+1)÷2a^2-a/a^+2a+1,其中a满足a^2-a-1=0
计算:[a-(1/a)]/a^2-2a+1/a
a-1/a+2÷a²-2a+1/a²-4×a+3/a²+a-6
化简:[(a-2)/(a²+2a)-(a-1)/(a²+4a+4)]÷(a-4)/(a+2)
化简:{(a+2/a²-2a)-(a-1/a²-4a+4)}÷(a-4/a)
a(a-1)(a-2)(a-3)(a-4)因式分解
a/a+2-1/a-1÷a+2/a²-2a+1
化简:(a/a-1-2a-1/a-1)÷a-1/a+2