化简cos(π/12-α)-根号3cos(5π/12+α)
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化简cos(π/12-α)-根号3cos(5π/12+α)化简cos(π/12-α)-根号3cos(5π/12+α)化简cos(π/12-α)-根号3cos(5π/12+α)cos(π/12-α)-√
化简cos(π/12-α)-根号3cos(5π/12+α)
化简cos(π/12-α)-根号3cos(5π/12+α)
化简cos(π/12-α)-根号3cos(5π/12+α)
cos(π/12-α)-√3cos(5π/12+α)
=2[(1/2)cos(π/12-α)-(√3/2)sin(π/12-α)] (∵cos(5π/12+α)=sin[π/2-(5π/12+α)]=sin(π/12-α))
=2sin[π/6-(π/12-α)]
=2sin(π/12+α)
答案是:2sin((π+α)/12)