先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1

先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1
先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1

先化简,再求值x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1),其中x=2倍根号3+1
您好：

x-4/(x²-1)除以x²-3x-4/(x²+2x+1)+1/(x-1)
=（x-4）/（x+1）（x-1）÷（x+1）（x-4）/(x+1)²+1/(x-1)
=1/(x-1)+1/(x-1)
=2/(x-1)
=2/(2√3+1-1)
=2/2√3
=1/√3
=√3/3


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