(x-4)/(x-5)+(x-8)/(x-9)-(x-5)/(x-6)-(x-7)/(x-8)分式计算

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(x-4)/(x-5)+(x-8)/(x-9)-(x-5)/(x-6)-(x-7)/(x-8)分式计算(x-4)/(x-5)+(x-8)/(x-9)-(x-5)/(x-6)-(x-7)/(x-8)分式

(x-4)/(x-5)+(x-8)/(x-9)-(x-5)/(x-6)-(x-7)/(x-8)分式计算
(x-4)/(x-5)+(x-8)/(x-9)-(x-5)/(x-6)-(x-7)/(x-8)分式计算

(x-4)/(x-5)+(x-8)/(x-9)-(x-5)/(x-6)-(x-7)/(x-8)分式计算
方法一：就是直接通分.
方法二：个人觉得算是比较简单的方法,省去了化简乘式的繁琐.见下：
（x-4)/(x-5)=1+1/(x-5)
以下同此化简可得式：1+1/(x-5)+1+1/(x-9)-[1+1/(x-6)]-[1+1/(x-8)]=
1/(x-5)+1/(x-9)-1/(x-6)-1/(x-8)=1/[(x-7)+2]+1/[(x-7)-2]-1/[(x-7)+1]-1/[(x-7)-1]
为了书写方便将上面的（x-7）用s代替,最后再代入.先得
2s/(s^2-4)-2s/(s^2-1)=2s*[1/(s^2-4)-1/(s^2-1)]
=2s*{1/[(s^2-2.5)-1.5]-1/[(s^2-2.5)+1.5]}
=2s*3/[(s^2-2.5)^2-1.5^2]
至此完成再将s用（x-7)代入即可.别看我写得这么长,其实方法真的还不错,计算量少了很多啊 ,楼主不妨看看这种方法.其实数学的思想就是（（（变）））啊!好好把握,

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