若2x^2-5x+2
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若2x^2-5x+2若2x^2-5x+2若2x^2-5x+22x^2-5x+2<0(2x-1)(x-2)<01/2<x<2从而2x-1>0 x-2<0于是
若2x^2-5x+2
若2x^2-5x+2<0,则根号1-4x+4x^2+2|x-2|=
若2x^2-5x+2
2x^2-5x+2<0
(2x-1)(x-2)<0
1/2<x<2
从而
2x-1>0 x-2<0
于是
原式
=根号(2x-1)²+2|x-2|
=2x-1-2(x-2)
=3
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