简化代数式(x²-1)/(x²+2x)×x/(x-1),并判断当x满足不等式组x+2-6时该代数式的符号x2-1 x2+2x ÷x-1 x =x2-1 x2+2x •x x-1 =(x -1)(x+1) x(x +2) •x x-1 =x+1 x+2 x+2＜1① 2(x-1)＞-6② 解不等式①，得x＜-1

简化代数式(x²-1)/(x²+2x)×x/(x-1),并判断当x满足不等式组x+2-6时该代数式的符号x2-1 x2+2x ÷x-1 x =x2-1 x2+2x •x x-1 =(x -1)(x+1) x(x +2) •x x-1 =x+1 x+2 x+2＜1① 2(x-1)＞-6② 解不等式①，得x＜-1
简化代数式(x²-1)/(x²+2x)×x/(x-1),并判断当x满足不等式组x+2-6时该代数式的符号
x2-1 x2+2x ÷x-1 x
=x2-1 x2+2x •x x-1
=(x -1)(x+1) x(x +2) •x x-1
=x+1 x+2
x+2＜1① 2(x-1)＞-6②
解不等式①，得x＜-1．
解不等式②，得x＞-2．
所以，不等式组 x+2＜1 2(x-1)＞-6 的解集是-2＜x＜-1．
当-2＜x＜-1时，x+1＜0，x+2＞0，
所以x+1 x+2 ＜0，即该代数式的符号为负号．
不用你们做了，正确答案是这样！

简化代数式(x²-1)/(x²+2x)×x/(x-1),并判断当x满足不等式组x+2-6时该代数式的符号x2-1 x2+2x ÷x-1 x =x2-1 x2+2x •x x-1 =(x -1)(x+1) x(x +2) •x x-1 =x+1 x+2 x+2＜1① 2(x-1)＞-6② 解不等式①，得x＜-1
(1 + x)/(2 + x)
符号小于0