(2m+1-3n)(2m-1+3n)=?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 03:02:04
(2m+1-3n)(2m-1+3n)=?(2m+1-3n)(2m-1+3n)=?(2m+1-3n)(2m-1+3n)=?(2m+1-3n)(2m-1+3n)=[2m+(1-3n)][2m-(1-3n)
(2m+1-3n)(2m-1+3n)=?
(2m+1-3n)(2m-1+3n)=?
(2m+1-3n)(2m-1+3n)=?
(2m+1-3n)(2m-1+3n)
=[2m+(1-3n)][2m-(1-3n)]
=(2m)^2-(1-3n)^2
=4m^2-(1-6n+9n^2)
=4m^2-1+6n-9n^2
=[2m+(1-3n)][2m-(1-3n)]
=(2m)²-(1-3n)²
=4m²-1+6n-9n²
1对于正整数n和m,定义nm!(m是下标)=(n-m)(n-2m)(n-3m)...(n-km),其中m
m/n=5/3,求(m/m+n)+(m/m+n)-(n^2/m^2-n^2)
已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))
(2m+n)(2m-n)+n(2m+n)-8m^2n^3/(2n^3) m=-2分之1,n=2013
若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值
若2m=3n,求分式(1+m/n-n/n-m)除以(1-m/n-n/n+m)的值
(m-2n)^2+(3m-n)(2m+2n)-(2m+n)(2m-n) 已知m+n=4 mn=1
2/(m+n)+3/(m-n)=3/2,1/(m+n)-9/(m-n)=-1,求m,n的值
如果m除以n=17,m,n都是自然数,那么m和n的最小公倍数是() 1、m 2、n 3、17 4、m*n
1/(m-n)-1/(m+n)-2n/(m^2+n^2)-4n^3/m^4+n^4)-8n^7/(m^8+n^8)-16n^15/(m^16+n^16)+32n^31/(n32-m32)
C(m,n)=n(n-1)(n-2)...(n-m+1)/m!中的!
(1),(-m-n)(-m+n) (2),(-m+n)(m-n)
m^2=n+2,n^2=m+2(m不等于n),求m^3-2mn+n^3的值因为m^2=n+2,n^2=m+2 所以 m^2-n^2=n-m 即 (m-n)(m+n)=n-m m+n=1为什么得m+n=1,求详解.
分解因式:(1)6a(m-n)^2-8a^2 (m-n)^3 (2)已知m、n均为整数,且有m(m-n)-n(n-m)=12,求m、n的值
(m-n)*(3m-2n+1)=?
解方程组:(m+n)-2(m-n)=1 3(m+n)+2(m-n)=3 (m+n)-2(m-n)=1 3(m+n)+2(m-n)=3 是这两个方程
(m-n)^3(n-m)^2(m-n)=_____
1若m=n,则|m|=|n|;2若m=—n,则|m|=|n|;3若|m|=|n|,则m=—n;4若|m|=|n|,则m=n哪个对