(x²-y²)/(x-y)-2x+y

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(x²-y²)/(x-y)-2x+y(x²-y²)/(x-y)-2x+y(x²-y²)/(x-y)-2x+y原式=(x+y)(x-y)/(x

(x²-y²)/(x-y)-2x+y
(x²-y²)/(x-y)-2x+y

(x²-y²)/(x-y)-2x+y
原式=(x+y)(x-y)/(x-y)-2x+y=x+y-2x+y=2y-x

(x²-y²)/(x-y)-2x+y
=(x+y)(x-y)/(x-y)-2x+y
=x+y-2x+y
=2y-x
说明：x≠y，要不然分母为0。