(x²-y²)/(x-y)-2x+y
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(x²-y²)/(x-y)-2x+y(x²-y²)/(x-y)-2x+y(x²-y²)/(x-y)-2x+y原式=(x+y)(x-y)/(x
(x²-y²)/(x-y)-2x+y
(x²-y²)/(x-y)-2x+y
(x²-y²)/(x-y)-2x+y
原式=(x+y)(x-y)/(x-y)-2x+y=x+y-2x+y=2y-x
(x²-y²)/(x-y)-2x+y
=(x+y)(x-y)/(x-y)-2x+y
=x+y-2x+y
=2y-x
说明:x≠y,要不然分母为0。