(2x+3))(x-4)-(x+2)(x-3)=x的平方-8
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(2x+3))(x-4)-(x+2)(x-3)=x的平方-8(2x+3))(x-4)-(x+2)(x-3)=x的平方-8(2x+3))(x-4)-(x+2)(x-3)=x的平方-82x^2-5x-12
(2x+3))(x-4)-(x+2)(x-3)=x的平方-8
(2x+3))(x-4)-(x+2)(x-3)=x的平方-8
(2x+3))(x-4)-(x+2)(x-3)=x的平方-8
2x^2-5x-12-x^2+x+6-x^2+8=0
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