若（x-y)^2=12,(x+y)^2=16,求xy的值
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若（x-y)^2=12,(x+y)^2=16,求xy的值若（x-y)^2=12,(x+y)^2=16,求xy的值若（x-y)^2=12,(x+y)^2=16,求xy的值(x+y)^2=16（x-y)^
若（x-y)^2=12,(x+y)^2=16,求xy的值
若（x-y)^2=12,(x+y)^2=16,求xy的值
若（x-y)^2=12,(x+y)^2=16,求xy的值
(x+y)^2=16
（x-y)^2=12
相减得
4xy=4
xy=1
解: （x-y)²=12. ,(x+y)²=16
4xy=(x+y)²-(x-y)²=16-12=4
xy=4÷4=1
祝你学习进步,如有不明可以追问.同意我的答案请采纳,O(∩_∩)O谢谢
（x-y)^2=12,(x+y)^2=16
(x+y)^2 -（x-y)^2
=4xy=4
xy=1
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